b^2+22b+120=0

Solution for b^2+22b+120=0 equation:

Simplifying
b2 + 22b + 120 = 0

Reorder the terms:
120 + 22b + b2 = 0

Solving
120 + 22b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(12 + b)(10 + b) = 0

Subproblem 1
Set the factor '(12 + b)' equal to zero and attempt to solve:

Simplifying
12 + b = 0

Solving
12 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + b = 0 + -12

Combine like terms: 12 + -12 = 0
0 + b = 0 + -12
b = 0 + -12

Combine like terms: 0 + -12 = -12
b = -12

Simplifying
b = -12
Subproblem 2
Set the factor '(10 + b)' equal to zero and attempt to solve:

Simplifying
10 + b = 0

Solving
10 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + b = 0 + -10

Combine like terms: 10 + -10 = 0
0 + b = 0 + -10
b = 0 + -10

Combine like terms: 0 + -10 = -10
b = -10

Simplifying
b = -10
Solution
b = {-12, -10}